4(3y+1)+13=5y+2

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Solution for 4(3y+1)+13=5y+2 equation: 



4(3y+1)+13=5y+2

We move all terms to the left:

4(3y+1)+13-(5y+2)=0

We multiply parentheses

12y-(5y+2)+4+13=0

We get rid of parentheses

12y-5y-2+4+13=0

We add all the numbers together, and all the variables

7y+15=0

We move all terms containing y to the left, all other terms to the right

7y=-15

y=-15/7

y=-2+1/7

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