4(3y+1)+2=3(4y+2)

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Solution for 4(3y+1)+2=3(4y+2) equation:



4(3y+1)+2=3(4y+2)
We move all terms to the left:
4(3y+1)+2-(3(4y+2))=0
We multiply parentheses
12y-(3(4y+2))+4+2=0
We calculate terms in parentheses: -(3(4y+2)), so:
3(4y+2)
We multiply parentheses
12y+6
Back to the equation:
-(12y+6)
We add all the numbers together, and all the variables
12y-(12y+6)+6=0
We get rid of parentheses
12y-12y-6+6=0
We add all the numbers together, and all the variables
=0
y=0/1
y=0

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