4(3y+1)-7=10y-8

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Solution for 4(3y+1)-7=10y-8 equation: 



4(3y+1)-7=10y-8

We move all terms to the left:

4(3y+1)-7-(10y-8)=0

We multiply parentheses

12y-(10y-8)+4-7=0

We get rid of parentheses

12y-10y+8+4-7=0

We add all the numbers together, and all the variables

2y+5=0

We move all terms containing y to the left, all other terms to the right

2y=-5

y=-5/2

y=-2+1/2

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