4(3y+1)-7y=6+5y-2

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Solution for 4(3y+1)-7y=6+5y-2 equation: 



4(3y+1)-7y=6+5y-2

We move all terms to the left:

4(3y+1)-7y-(6+5y-2)=0

We add all the numbers together, and all the variables

4(3y+1)-7y-(5y+4)=0

We add all the numbers together, and all the variables

-7y+4(3y+1)-(5y+4)=0

We multiply parentheses

-7y+12y-(5y+4)+4=0

We get rid of parentheses

-7y+12y-5y-4+4=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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