4(3y+1)=11

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Solution for 4(3y+1)=11 equation: 



4(3y+1)=11

We move all terms to the left:

4(3y+1)-(11)=0

We multiply parentheses

12y+4-11=0

We add all the numbers together, and all the variables

12y-7=0

We move all terms containing y to the left, all other terms to the right

12y=7

y=7/12

y=7/12

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