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4(3y+1)=6(3+1y)
We move all terms to the left:
4(3y+1)-(6(3+1y))=0
We add all the numbers together, and all the variables
4(3y+1)-(6(y+3))=0
We multiply parentheses
12y-(6(y+3))+4=0
We calculate terms in parentheses: -(6(y+3)), so:We get rid of parentheses
6(y+3)
We multiply parentheses
6y+18
Back to the equation:
-(6y+18)
12y-6y-18+4=0
We add all the numbers together, and all the variables
6y-14=0
We move all terms containing y to the left, all other terms to the right
6y=14
y=14/6
y=2+1/3
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