4(3y+2)+3(2z-3)=61

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Solution for 4(3y+2)+3(2z-3)=61 equation:


Simplifying
4(3y + 2) + 3(2z + -3) = 61

Reorder the terms:
4(2 + 3y) + 3(2z + -3) = 61
(2 * 4 + 3y * 4) + 3(2z + -3) = 61
(8 + 12y) + 3(2z + -3) = 61

Reorder the terms:
8 + 12y + 3(-3 + 2z) = 61
8 + 12y + (-3 * 3 + 2z * 3) = 61
8 + 12y + (-9 + 6z) = 61

Reorder the terms:
8 + -9 + 12y + 6z = 61

Combine like terms: 8 + -9 = -1
-1 + 12y + 6z = 61

Solving
-1 + 12y + 6z = 61

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 12y + 1 + 6z = 61 + 1

Reorder the terms:
-1 + 1 + 12y + 6z = 61 + 1

Combine like terms: -1 + 1 = 0
0 + 12y + 6z = 61 + 1
12y + 6z = 61 + 1

Combine like terms: 61 + 1 = 62
12y + 6z = 62

Add '-6z' to each side of the equation.
12y + 6z + -6z = 62 + -6z

Combine like terms: 6z + -6z = 0
12y + 0 = 62 + -6z
12y = 62 + -6z

Divide each side by '12'.
y = 5.166666667 + -0.5z

Simplifying
y = 5.166666667 + -0.5z

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