4(3y+2)+5(2y+3)=111

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Solution for 4(3y+2)+5(2y+3)=111 equation:


Simplifying
4(3y + 2) + 5(2y + 3) = 111

Reorder the terms:
4(2 + 3y) + 5(2y + 3) = 111
(2 * 4 + 3y * 4) + 5(2y + 3) = 111
(8 + 12y) + 5(2y + 3) = 111

Reorder the terms:
8 + 12y + 5(3 + 2y) = 111
8 + 12y + (3 * 5 + 2y * 5) = 111
8 + 12y + (15 + 10y) = 111

Reorder the terms:
8 + 15 + 12y + 10y = 111

Combine like terms: 8 + 15 = 23
23 + 12y + 10y = 111

Combine like terms: 12y + 10y = 22y
23 + 22y = 111

Solving
23 + 22y = 111

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-23' to each side of the equation.
23 + -23 + 22y = 111 + -23

Combine like terms: 23 + -23 = 0
0 + 22y = 111 + -23
22y = 111 + -23

Combine like terms: 111 + -23 = 88
22y = 88

Divide each side by '22'.
y = 4

Simplifying
y = 4

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