4(3y+2)-7=4y+65

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Solution for 4(3y+2)-7=4y+65 equation: 



4(3y+2)-7=4y+65

We move all terms to the left:

4(3y+2)-7-(4y+65)=0

We multiply parentheses

12y-(4y+65)+8-7=0

We get rid of parentheses

12y-4y-65+8-7=0

We add all the numbers together, and all the variables

8y-64=0

We move all terms containing y to the left, all other terms to the right

8y=64

y=64/8

y=8

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