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4(3y+2)=4(2y+3)+4y
We move all terms to the left:
4(3y+2)-(4(2y+3)+4y)=0
We multiply parentheses
12y-(4(2y+3)+4y)+8=0
We calculate terms in parentheses: -(4(2y+3)+4y), so:We get rid of parentheses
4(2y+3)+4y
We add all the numbers together, and all the variables
4y+4(2y+3)
We multiply parentheses
4y+8y+12
We add all the numbers together, and all the variables
12y+12
Back to the equation:
-(12y+12)
12y-12y-12+8=0
We add all the numbers together, and all the variables
-4!=0
There is no solution for this equation
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