4(3y+3)=6-2(y-3)

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Solution for 4(3y+3)=6-2(y-3) equation: 



4(3y+3)=6-2(y-3)

We move all terms to the left:

4(3y+3)-(6-2(y-3))=0

We multiply parentheses

12y-(6-2(y-3))+12=0



We calculate terms in parentheses: -(6-2(y-3)), so:

6-2(y-3)

determiningTheFunctionDomain
-2(y-3)+6

We multiply parentheses

-2y+6+6

We add all the numbers together, and all the variables

-2y+12

Back to the equation:

-(-2y+12)



We get rid of parentheses

12y+2y-12+12=0

We add all the numbers together, and all the variables

14y=0

y=0/14

y=0

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