4(3y+4.1)=18

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Solution for 4(3y+4.1)=18 equation: 



4(3y+4.1)=18

We move all terms to the left:

4(3y+4.1)-(18)=0

We multiply parentheses

12y+16.4-18=0

We add all the numbers together, and all the variables

12y-1.6=0

We move all terms containing y to the left, all other terms to the right

12y=1.6

y=1.6/12

y=1/7.5

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