4(3y+5)=10-2(y-5)

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Solution for 4(3y+5)=10-2(y-5) equation:


Simplifying
4(3y + 5) = 10 + -2(y + -5)

Reorder the terms:
4(5 + 3y) = 10 + -2(y + -5)
(5 * 4 + 3y * 4) = 10 + -2(y + -5)
(20 + 12y) = 10 + -2(y + -5)

Reorder the terms:
20 + 12y = 10 + -2(-5 + y)
20 + 12y = 10 + (-5 * -2 + y * -2)
20 + 12y = 10 + (10 + -2y)

Combine like terms: 10 + 10 = 20
20 + 12y = 20 + -2y

Add '-20' to each side of the equation.
20 + -20 + 12y = 20 + -20 + -2y

Combine like terms: 20 + -20 = 0
0 + 12y = 20 + -20 + -2y
12y = 20 + -20 + -2y

Combine like terms: 20 + -20 = 0
12y = 0 + -2y
12y = -2y

Solving
12y = -2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '2y' to each side of the equation.
12y + 2y = -2y + 2y

Combine like terms: 12y + 2y = 14y
14y = -2y + 2y

Combine like terms: -2y + 2y = 0
14y = 0

Divide each side by '14'.
y = 0

Simplifying
y = 0

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