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4(3y+5)=2(10y-14)
We move all terms to the left:
4(3y+5)-(2(10y-14))=0
We multiply parentheses
12y-(2(10y-14))+20=0
We calculate terms in parentheses: -(2(10y-14)), so:We get rid of parentheses
2(10y-14)
We multiply parentheses
20y-28
Back to the equation:
-(20y-28)
12y-20y+28+20=0
We add all the numbers together, and all the variables
-8y+48=0
We move all terms containing y to the left, all other terms to the right
-8y=-48
y=-48/-8
y=+6
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