4(3y+5)=y-8(-y-4)

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Solution for 4(3y+5)=y-8(-y-4) equation: 



4(3y+5)=y-8(-y-4)

We move all terms to the left:

4(3y+5)-(y-8(-y-4))=0

We add all the numbers together, and all the variables

4(3y+5)-(y-8(-1y-4))=0

We multiply parentheses

12y-(y-8(-1y-4))+20=0



We calculate terms in parentheses: -(y-8(-1y-4)), so:

y-8(-1y-4)

We multiply parentheses

y+8y+32

We add all the numbers together, and all the variables

9y+32

Back to the equation:

-(9y+32)



We get rid of parentheses

12y-9y-32+20=0

We add all the numbers together, and all the variables

3y-12=0

We move all terms containing y to the left, all other terms to the right

3y=12

y=12/3

y=4

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