4(3y+7)=160

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Solution for 4(3y+7)=160 equation: 



4(3y+7)=160

We move all terms to the left:

4(3y+7)-(160)=0

We multiply parentheses

12y+28-160=0

We add all the numbers together, and all the variables

12y-132=0

We move all terms containing y to the left, all other terms to the right

12y=132

y=132/12

y=11

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