4(3y+8)=28y

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Solution for 4(3y+8)=28y equation:



4(3y+8)=28y
We move all terms to the left:
4(3y+8)-(28y)=0
We add all the numbers together, and all the variables
-28y+4(3y+8)=0
We multiply parentheses
-28y+12y+32=0
We add all the numbers together, and all the variables
-16y+32=0
We move all terms containing y to the left, all other terms to the right
-16y=-32
y=-32/-16
y=+2

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