4(3y+8)=y+3=128

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Solution for 4(3y+8)=y+3=128 equation: 



4(3y+8)=y+3=128

We move all terms to the left:

4(3y+8)-(y+3)=0

We multiply parentheses

12y-(y+3)+32=0

We get rid of parentheses

12y-y-3+32=0

We add all the numbers together, and all the variables

11y+29=0

We move all terms containing y to the left, all other terms to the right

11y=-29

y=-29/11

y=-2+7/11

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