4(3y-1)+13=5y=2

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Solution for 4(3y-1)+13=5y=2 equation:



4(3y-1)+13=5y=2
We move all terms to the left:
4(3y-1)+13-(5y)=0
We add all the numbers together, and all the variables
-5y+4(3y-1)+13=0
We multiply parentheses
-5y+12y-4+13=0
We add all the numbers together, and all the variables
7y+9=0
We move all terms containing y to the left, all other terms to the right
7y=-9
y=-9/7
y=-1+2/7

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