4(3y-1)+13=5y=2

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Solution for 4(3y-1)+13=5y=2 equation: 



4(3y-1)+13=5y=2

We move all terms to the left:

4(3y-1)+13-(5y)=0

We add all the numbers together, and all the variables

-5y+4(3y-1)+13=0

We multiply parentheses

-5y+12y-4+13=0

We add all the numbers together, and all the variables

7y+9=0

We move all terms containing y to the left, all other terms to the right

7y=-9

y=-9/7

y=-1+2/7

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