4(3y-1)=12y-4

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Solution for 4(3y-1)=12y-4 equation: 


Simplifying
4(3y + -1) = 12y + -4

Reorder the terms:
4(-1 + 3y) = 12y + -4
(-1 * 4 + 3y * 4) = 12y + -4
(-4 + 12y) = 12y + -4

Reorder the terms:
-4 + 12y = -4 + 12y

Add '4' to each side of the equation.
-4 + 4 + 12y = -4 + 4 + 12y

Combine like terms: -4 + 4 = 0
0 + 12y = -4 + 4 + 12y
12y = -4 + 4 + 12y

Combine like terms: -4 + 4 = 0
12y = 0 + 12y
12y = 12y

Add '-12y' to each side of the equation.
12y + -12y = 12y + -12y

Combine like terms: 12y + -12y = 0
0 = 12y + -12y

Combine like terms: 12y + -12y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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