4(3y-2)+23=21-(2y-1)

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Solution for 4(3y-2)+23=21-(2y-1) equation: 



4(3y-2)+23=21-(2y-1)

We move all terms to the left:

4(3y-2)+23-(21-(2y-1))=0

We multiply parentheses

12y-(21-(2y-1))-8+23=0



We calculate terms in parentheses: -(21-(2y-1)), so:

21-(2y-1)

determiningTheFunctionDomain
-(2y-1)+21

We get rid of parentheses

-2y+1+21

We add all the numbers together, and all the variables

-2y+22

Back to the equation:

-(-2y+22)



We add all the numbers together, and all the variables

12y-(-2y+22)+15=0

We get rid of parentheses

12y+2y-22+15=0

We add all the numbers together, and all the variables

14y-7=0

We move all terms containing y to the left, all other terms to the right

14y=7

y=7/14

y=1/2

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