4(3y-2)+4y=-56

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Solution for 4(3y-2)+4y=-56 equation: 



4(3y-2)+4y=-56

We move all terms to the left:

4(3y-2)+4y-(-56)=0

We add all the numbers together, and all the variables

4y+4(3y-2)+56=0

We multiply parentheses

4y+12y-8+56=0

We add all the numbers together, and all the variables

16y+48=0

We move all terms containing y to the left, all other terms to the right

16y=-48

y=-48/16

y=-3

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