4(3y-2)-5(y-6)=y+8

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Solution for 4(3y-2)-5(y-6)=y+8 equation: 



4(3y-2)-5(y-6)=y+8

We move all terms to the left:

4(3y-2)-5(y-6)-(y+8)=0

We multiply parentheses

12y-5y-(y+8)-8+30=0

We get rid of parentheses

12y-5y-y-8-8+30=0

We add all the numbers together, and all the variables

6y+14=0

We move all terms containing y to the left, all other terms to the right

6y=-14

y=-14/6

y=-2+1/3

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