4(3y-2)/7=3y-5

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Solution for 4(3y-2)/7=3y-5 equation:


y in (-oo:+oo)

(4*(3*y-2))/7 = 3*y-5 // - 3*y-5

(4*(3*y-2))/7-(3*y)+5 = 0

(4*(3*y-2))/7-3*y+5 = 0

(4*(3*y-2))/7+(-3*7*y)/7+(5*7)/7 = 0

4*(3*y-2)-3*7*y+5*7 = 0

35-9*y-8 = 0

27-9*y = 0

(27-9*y)/7 = 0

(27-9*y)/7 = 0 // * 7

27-9*y = 0

27-9*y = 0 // - 27

-9*y = -27 // : -9

y = -27/(-9)

y = 3

y = 3

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