4(3y-2)=2y-5

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Solution for 4(3y-2)=2y-5 equation:



4(3y-2)=2y-5
We move all terms to the left:
4(3y-2)-(2y-5)=0
We multiply parentheses
12y-(2y-5)-8=0
We get rid of parentheses
12y-2y+5-8=0
We add all the numbers together, and all the variables
10y-3=0
We move all terms containing y to the left, all other terms to the right
10y=3
y=3/10
y=3/10

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