4(3y-3)+3(4y+4)=4y+40

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Solution for 4(3y-3)+3(4y+4)=4y+40 equation: 



4(3y-3)+3(4y+4)=4y+40

We move all terms to the left:

4(3y-3)+3(4y+4)-(4y+40)=0

We multiply parentheses

12y+12y-(4y+40)-12+12=0

We get rid of parentheses

12y+12y-4y-40-12+12=0

We add all the numbers together, and all the variables

20y-40=0

We move all terms containing y to the left, all other terms to the right

20y=40

y=40/20

y=2

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