4(3y-3)-2(3y-5)=7

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Solution for 4(3y-3)-2(3y-5)=7 equation: 



4(3y-3)-2(3y-5)=7

We move all terms to the left:

4(3y-3)-2(3y-5)-(7)=0

We multiply parentheses

12y-6y-12+10-7=0

We add all the numbers together, and all the variables

6y-9=0

We move all terms containing y to the left, all other terms to the right

6y=9

y=9/6

y=1+1/2

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