4(3y-4)+7y=4y+14

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Solution for 4(3y-4)+7y=4y+14 equation: 



4(3y-4)+7y=4y+14

We move all terms to the left:

4(3y-4)+7y-(4y+14)=0

We add all the numbers together, and all the variables

7y+4(3y-4)-(4y+14)=0

We multiply parentheses

7y+12y-(4y+14)-16=0

We get rid of parentheses

7y+12y-4y-14-16=0

We add all the numbers together, and all the variables

15y-30=0

We move all terms containing y to the left, all other terms to the right

15y=30

y=30/15

y=2

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