4(3y-4)=8(y+2)

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Solution for 4(3y-4)=8(y+2) equation: 



4(3y-4)=8(y+2)

We move all terms to the left:

4(3y-4)-(8(y+2))=0

We multiply parentheses

12y-(8(y+2))-16=0



We calculate terms in parentheses: -(8(y+2)), so:

8(y+2)

We multiply parentheses

8y+16

Back to the equation:

-(8y+16)



We get rid of parentheses

12y-8y-16-16=0

We add all the numbers together, and all the variables

4y-32=0

We move all terms containing y to the left, all other terms to the right

4y=32

y=32/4

y=8

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