4(3y-5)=-2(-6+10)

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Solution for 4(3y-5)=-2(-6+10) equation: 



4(3y-5)=-2(-6+10)

We move all terms to the left:

4(3y-5)-(-2(-6+10))=0

We add all the numbers together, and all the variables

4(3y-5)-(-24)=0

We add all the numbers together, and all the variables

4(3y-5)+24=0

We multiply parentheses

12y-20+24=0

We add all the numbers together, and all the variables

12y+4=0

We move all terms containing y to the left, all other terms to the right

12y=-4

y=-4/12

y=-1/3

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