4(3y-5)=10y+6

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Solution for 4(3y-5)=10y+6 equation: 



4(3y-5)=10y+6

We move all terms to the left:

4(3y-5)-(10y+6)=0

We multiply parentheses

12y-(10y+6)-20=0

We get rid of parentheses

12y-10y-6-20=0

We add all the numbers together, and all the variables

2y-26=0

We move all terms containing y to the left, all other terms to the right

2y=26

y=26/2

y=13

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