4(3y-5)=2(3y-4)

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Solution for 4(3y-5)=2(3y-4) equation: 



4(3y-5)=2(3y-4)

We move all terms to the left:

4(3y-5)-(2(3y-4))=0

We multiply parentheses

12y-(2(3y-4))-20=0



We calculate terms in parentheses: -(2(3y-4)), so:

2(3y-4)

We multiply parentheses

6y-8

Back to the equation:

-(6y-8)



We get rid of parentheses

12y-6y+8-20=0

We add all the numbers together, and all the variables

6y-12=0

We move all terms containing y to the left, all other terms to the right

6y=12

y=12/6

y=2

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