4(3y-5)=5(5y-27)

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Solution for 4(3y-5)=5(5y-27) equation: 



4(3y-5)=5(5y-27)

We move all terms to the left:

4(3y-5)-(5(5y-27))=0

We multiply parentheses

12y-(5(5y-27))-20=0



We calculate terms in parentheses: -(5(5y-27)), so:

5(5y-27)

We multiply parentheses

25y-135

Back to the equation:

-(25y-135)



We get rid of parentheses

12y-25y+135-20=0

We add all the numbers together, and all the variables

-13y+115=0

We move all terms containing y to the left, all other terms to the right

-13y=-115

y=-115/-13

y=8+11/13

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