4(3y-7)=9(y+3)

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Solution for 4(3y-7)=9(y+3) equation: 



4(3y-7)=9(y+3)

We move all terms to the left:

4(3y-7)-(9(y+3))=0

We multiply parentheses

12y-(9(y+3))-28=0



We calculate terms in parentheses: -(9(y+3)), so:

9(y+3)

We multiply parentheses

9y+27

Back to the equation:

-(9y+27)



We get rid of parentheses

12y-9y-27-28=0

We add all the numbers together, and all the variables

3y-55=0

We move all terms containing y to the left, all other terms to the right

3y=55

y=55/3

y=18+1/3

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