4(3z+1)-2=12(z-2)+26

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Solution for 4(3z+1)-2=12(z-2)+26 equation: 



4(3z+1)-2=12(z-2)+26

We move all terms to the left:

4(3z+1)-2-(12(z-2)+26)=0

We multiply parentheses

12z-(12(z-2)+26)+4-2=0



We calculate terms in parentheses: -(12(z-2)+26), so:

12(z-2)+26

We multiply parentheses

12z-24+26

We add all the numbers together, and all the variables

12z+2

Back to the equation:

-(12z+2)



We add all the numbers together, and all the variables

12z-(12z+2)+2=0

We get rid of parentheses

12z-12z-2+2=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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