4(3z+1)-9=67

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Solution for 4(3z+1)-9=67 equation: 



4(3z+1)-9=67

We move all terms to the left:

4(3z+1)-9-(67)=0

We add all the numbers together, and all the variables

4(3z+1)-76=0

We multiply parentheses

12z+4-76=0

We add all the numbers together, and all the variables

12z-72=0

We move all terms containing z to the left, all other terms to the right

12z=72

z=72/12

z=6

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