4(3z+10)=7b-12-b

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Solution for 4(3z+10)=7b-12-b equation:


Simplifying
4(3z + 10) = 7b + -12 + -1b

Reorder the terms:
4(10 + 3z) = 7b + -12 + -1b
(10 * 4 + 3z * 4) = 7b + -12 + -1b
(40 + 12z) = 7b + -12 + -1b

Reorder the terms:
40 + 12z = -12 + 7b + -1b

Combine like terms: 7b + -1b = 6b
40 + 12z = -12 + 6b

Solving
40 + 12z = -12 + 6b

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-40' to each side of the equation.
40 + -40 + 12z = -12 + -40 + 6b

Combine like terms: 40 + -40 = 0
0 + 12z = -12 + -40 + 6b
12z = -12 + -40 + 6b

Combine like terms: -12 + -40 = -52
12z = -52 + 6b

Divide each side by '12'.
z = -4.333333333 + 0.5b

Simplifying
z = -4.333333333 + 0.5b

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