4(3z+2)=12(z-1)+19

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Solution for 4(3z+2)=12(z-1)+19 equation: 



4(3z+2)=12(z-1)+19

We move all terms to the left:

4(3z+2)-(12(z-1)+19)=0

We multiply parentheses

12z-(12(z-1)+19)+8=0



We calculate terms in parentheses: -(12(z-1)+19), so:

12(z-1)+19

We multiply parentheses

12z-12+19

We add all the numbers together, and all the variables

12z+7

Back to the equation:

-(12z+7)



We get rid of parentheses

12z-12z-7+8=0

We add all the numbers together, and all the variables

1!=0

There is no solution for this equation

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