4(3z+3)=3-3(z-3)

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Solution for 4(3z+3)=3-3(z-3) equation:


Simplifying
4(3z + 3) = 3 + -3(z + -3)

Reorder the terms:
4(3 + 3z) = 3 + -3(z + -3)
(3 * 4 + 3z * 4) = 3 + -3(z + -3)
(12 + 12z) = 3 + -3(z + -3)

Reorder the terms:
12 + 12z = 3 + -3(-3 + z)
12 + 12z = 3 + (-3 * -3 + z * -3)
12 + 12z = 3 + (9 + -3z)

Combine like terms: 3 + 9 = 12
12 + 12z = 12 + -3z

Add '-12' to each side of the equation.
12 + -12 + 12z = 12 + -12 + -3z

Combine like terms: 12 + -12 = 0
0 + 12z = 12 + -12 + -3z
12z = 12 + -12 + -3z

Combine like terms: 12 + -12 = 0
12z = 0 + -3z
12z = -3z

Solving
12z = -3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '3z' to each side of the equation.
12z + 3z = -3z + 3z

Combine like terms: 12z + 3z = 15z
15z = -3z + 3z

Combine like terms: -3z + 3z = 0
15z = 0

Divide each side by '15'.
z = 0

Simplifying
z = 0

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