4(3z+5)=10-2(z-5)

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Solution for 4(3z+5)=10-2(z-5) equation:


Simplifying
4(3z + 5) = 10 + -2(z + -5)

Reorder the terms:
4(5 + 3z) = 10 + -2(z + -5)
(5 * 4 + 3z * 4) = 10 + -2(z + -5)
(20 + 12z) = 10 + -2(z + -5)

Reorder the terms:
20 + 12z = 10 + -2(-5 + z)
20 + 12z = 10 + (-5 * -2 + z * -2)
20 + 12z = 10 + (10 + -2z)

Combine like terms: 10 + 10 = 20
20 + 12z = 20 + -2z

Add '-20' to each side of the equation.
20 + -20 + 12z = 20 + -20 + -2z

Combine like terms: 20 + -20 = 0
0 + 12z = 20 + -20 + -2z
12z = 20 + -20 + -2z

Combine like terms: 20 + -20 = 0
12z = 0 + -2z
12z = -2z

Solving
12z = -2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '2z' to each side of the equation.
12z + 2z = -2z + 2z

Combine like terms: 12z + 2z = 14z
14z = -2z + 2z

Combine like terms: -2z + 2z = 0
14z = 0

Divide each side by '14'.
z = 0

Simplifying
z = 0

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