4(3z-1)-2(z+1)=7(z+1)

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Solution for 4(3z-1)-2(z+1)=7(z+1) equation:


Simplifying
4(3z + -1) + -2(z + 1) = 7(z + 1)

Reorder the terms:
4(-1 + 3z) + -2(z + 1) = 7(z + 1)
(-1 * 4 + 3z * 4) + -2(z + 1) = 7(z + 1)
(-4 + 12z) + -2(z + 1) = 7(z + 1)

Reorder the terms:
-4 + 12z + -2(1 + z) = 7(z + 1)
-4 + 12z + (1 * -2 + z * -2) = 7(z + 1)
-4 + 12z + (-2 + -2z) = 7(z + 1)

Reorder the terms:
-4 + -2 + 12z + -2z = 7(z + 1)

Combine like terms: -4 + -2 = -6
-6 + 12z + -2z = 7(z + 1)

Combine like terms: 12z + -2z = 10z
-6 + 10z = 7(z + 1)

Reorder the terms:
-6 + 10z = 7(1 + z)
-6 + 10z = (1 * 7 + z * 7)
-6 + 10z = (7 + 7z)

Solving
-6 + 10z = 7 + 7z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-7z' to each side of the equation.
-6 + 10z + -7z = 7 + 7z + -7z

Combine like terms: 10z + -7z = 3z
-6 + 3z = 7 + 7z + -7z

Combine like terms: 7z + -7z = 0
-6 + 3z = 7 + 0
-6 + 3z = 7

Add '6' to each side of the equation.
-6 + 6 + 3z = 7 + 6

Combine like terms: -6 + 6 = 0
0 + 3z = 7 + 6
3z = 7 + 6

Combine like terms: 7 + 6 = 13
3z = 13

Divide each side by '3'.
z = 4.333333333

Simplifying
z = 4.333333333

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