4(3z-1)-3(z+4)=7(z+1)

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Solution for 4(3z-1)-3(z+4)=7(z+1) equation: 



4(3z-1)-3(z+4)=7(z+1)

We move all terms to the left:

4(3z-1)-3(z+4)-(7(z+1))=0

We multiply parentheses

12z-3z-(7(z+1))-4-12=0



We calculate terms in parentheses: -(7(z+1)), so:

7(z+1)

We multiply parentheses

7z+7

Back to the equation:

-(7z+7)



We add all the numbers together, and all the variables

9z-(7z+7)-16=0

We get rid of parentheses

9z-7z-7-16=0

We add all the numbers together, and all the variables

2z-23=0

We move all terms containing z to the left, all other terms to the right

2z=23

z=23/2

z=11+1/2

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