4(3z-1)-3(z+6)=2(z+1)

Solution for 4(3z-1)-3(z+6)=2(z+1) equation:

Simplifying
4(3z + -1) + -3(z + 6) = 2(z + 1)

Reorder the terms:
4(-1 + 3z) + -3(z + 6) = 2(z + 1)
(-1 * 4 + 3z * 4) + -3(z + 6) = 2(z + 1)
(-4 + 12z) + -3(z + 6) = 2(z + 1)

Reorder the terms:
-4 + 12z + -3(6 + z) = 2(z + 1)
-4 + 12z + (6 * -3 + z * -3) = 2(z + 1)
-4 + 12z + (-18 + -3z) = 2(z + 1)

Reorder the terms:
-4 + -18 + 12z + -3z = 2(z + 1)

Combine like terms: -4 + -18 = -22
-22 + 12z + -3z = 2(z + 1)

Combine like terms: 12z + -3z = 9z
-22 + 9z = 2(z + 1)

Reorder the terms:
-22 + 9z = 2(1 + z)
-22 + 9z = (1 * 2 + z * 2)
-22 + 9z = (2 + 2z)

Solving
-22 + 9z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-22 + 9z + -2z = 2 + 2z + -2z

Combine like terms: 9z + -2z = 7z
-22 + 7z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-22 + 7z = 2 + 0
-22 + 7z = 2

Add '22' to each side of the equation.
-22 + 22 + 7z = 2 + 22

Combine like terms: -22 + 22 = 0
0 + 7z = 2 + 22
7z = 2 + 22

Combine like terms: 2 + 22 = 24
7z = 24

Divide each side by '7'.
z = 3.428571429

Simplifying
z = 3.428571429