4(3z-1)-4(z+2)=5(z+1)

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Solution for 4(3z-1)-4(z+2)=5(z+1) equation:


Simplifying
4(3z + -1) + -4(z + 2) = 5(z + 1)

Reorder the terms:
4(-1 + 3z) + -4(z + 2) = 5(z + 1)
(-1 * 4 + 3z * 4) + -4(z + 2) = 5(z + 1)
(-4 + 12z) + -4(z + 2) = 5(z + 1)

Reorder the terms:
-4 + 12z + -4(2 + z) = 5(z + 1)
-4 + 12z + (2 * -4 + z * -4) = 5(z + 1)
-4 + 12z + (-8 + -4z) = 5(z + 1)

Reorder the terms:
-4 + -8 + 12z + -4z = 5(z + 1)

Combine like terms: -4 + -8 = -12
-12 + 12z + -4z = 5(z + 1)

Combine like terms: 12z + -4z = 8z
-12 + 8z = 5(z + 1)

Reorder the terms:
-12 + 8z = 5(1 + z)
-12 + 8z = (1 * 5 + z * 5)
-12 + 8z = (5 + 5z)

Solving
-12 + 8z = 5 + 5z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-5z' to each side of the equation.
-12 + 8z + -5z = 5 + 5z + -5z

Combine like terms: 8z + -5z = 3z
-12 + 3z = 5 + 5z + -5z

Combine like terms: 5z + -5z = 0
-12 + 3z = 5 + 0
-12 + 3z = 5

Add '12' to each side of the equation.
-12 + 12 + 3z = 5 + 12

Combine like terms: -12 + 12 = 0
0 + 3z = 5 + 12
3z = 5 + 12

Combine like terms: 5 + 12 = 17
3z = 17

Divide each side by '3'.
z = 5.666666667

Simplifying
z = 5.666666667

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