4(3z-1)-4(z+4)=3(z+1)

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Solution for 4(3z-1)-4(z+4)=3(z+1) equation:


Simplifying
4(3z + -1) + -4(z + 4) = 3(z + 1)

Reorder the terms:
4(-1 + 3z) + -4(z + 4) = 3(z + 1)
(-1 * 4 + 3z * 4) + -4(z + 4) = 3(z + 1)
(-4 + 12z) + -4(z + 4) = 3(z + 1)

Reorder the terms:
-4 + 12z + -4(4 + z) = 3(z + 1)
-4 + 12z + (4 * -4 + z * -4) = 3(z + 1)
-4 + 12z + (-16 + -4z) = 3(z + 1)

Reorder the terms:
-4 + -16 + 12z + -4z = 3(z + 1)

Combine like terms: -4 + -16 = -20
-20 + 12z + -4z = 3(z + 1)

Combine like terms: 12z + -4z = 8z
-20 + 8z = 3(z + 1)

Reorder the terms:
-20 + 8z = 3(1 + z)
-20 + 8z = (1 * 3 + z * 3)
-20 + 8z = (3 + 3z)

Solving
-20 + 8z = 3 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-20 + 8z + -3z = 3 + 3z + -3z

Combine like terms: 8z + -3z = 5z
-20 + 5z = 3 + 3z + -3z

Combine like terms: 3z + -3z = 0
-20 + 5z = 3 + 0
-20 + 5z = 3

Add '20' to each side of the equation.
-20 + 20 + 5z = 3 + 20

Combine like terms: -20 + 20 = 0
0 + 5z = 3 + 20
5z = 3 + 20

Combine like terms: 3 + 20 = 23
5z = 23

Divide each side by '5'.
z = 4.6

Simplifying
z = 4.6

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