4(3z-1)-5(z+1)=4(z+1)

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Solution for 4(3z-1)-5(z+1)=4(z+1) equation:


Simplifying
4(3z + -1) + -5(z + 1) = 4(z + 1)

Reorder the terms:
4(-1 + 3z) + -5(z + 1) = 4(z + 1)
(-1 * 4 + 3z * 4) + -5(z + 1) = 4(z + 1)
(-4 + 12z) + -5(z + 1) = 4(z + 1)

Reorder the terms:
-4 + 12z + -5(1 + z) = 4(z + 1)
-4 + 12z + (1 * -5 + z * -5) = 4(z + 1)
-4 + 12z + (-5 + -5z) = 4(z + 1)

Reorder the terms:
-4 + -5 + 12z + -5z = 4(z + 1)

Combine like terms: -4 + -5 = -9
-9 + 12z + -5z = 4(z + 1)

Combine like terms: 12z + -5z = 7z
-9 + 7z = 4(z + 1)

Reorder the terms:
-9 + 7z = 4(1 + z)
-9 + 7z = (1 * 4 + z * 4)
-9 + 7z = (4 + 4z)

Solving
-9 + 7z = 4 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-9 + 7z + -4z = 4 + 4z + -4z

Combine like terms: 7z + -4z = 3z
-9 + 3z = 4 + 4z + -4z

Combine like terms: 4z + -4z = 0
-9 + 3z = 4 + 0
-9 + 3z = 4

Add '9' to each side of the equation.
-9 + 9 + 3z = 4 + 9

Combine like terms: -9 + 9 = 0
0 + 3z = 4 + 9
3z = 4 + 9

Combine like terms: 4 + 9 = 13
3z = 13

Divide each side by '3'.
z = 4.333333333

Simplifying
z = 4.333333333

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