4(3z-1)-5(z+2)=3(z+1)

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Solution for 4(3z-1)-5(z+2)=3(z+1) equation:


Simplifying
4(3z + -1) + -5(z + 2) = 3(z + 1)

Reorder the terms:
4(-1 + 3z) + -5(z + 2) = 3(z + 1)
(-1 * 4 + 3z * 4) + -5(z + 2) = 3(z + 1)
(-4 + 12z) + -5(z + 2) = 3(z + 1)

Reorder the terms:
-4 + 12z + -5(2 + z) = 3(z + 1)
-4 + 12z + (2 * -5 + z * -5) = 3(z + 1)
-4 + 12z + (-10 + -5z) = 3(z + 1)

Reorder the terms:
-4 + -10 + 12z + -5z = 3(z + 1)

Combine like terms: -4 + -10 = -14
-14 + 12z + -5z = 3(z + 1)

Combine like terms: 12z + -5z = 7z
-14 + 7z = 3(z + 1)

Reorder the terms:
-14 + 7z = 3(1 + z)
-14 + 7z = (1 * 3 + z * 3)
-14 + 7z = (3 + 3z)

Solving
-14 + 7z = 3 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-14 + 7z + -3z = 3 + 3z + -3z

Combine like terms: 7z + -3z = 4z
-14 + 4z = 3 + 3z + -3z

Combine like terms: 3z + -3z = 0
-14 + 4z = 3 + 0
-14 + 4z = 3

Add '14' to each side of the equation.
-14 + 14 + 4z = 3 + 14

Combine like terms: -14 + 14 = 0
0 + 4z = 3 + 14
4z = 3 + 14

Combine like terms: 3 + 14 = 17
4z = 17

Divide each side by '4'.
z = 4.25

Simplifying
z = 4.25

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