4(3z-1)-5(z+4)=2(z+1)

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Solution for 4(3z-1)-5(z+4)=2(z+1) equation:


Simplifying
4(3z + -1) + -5(z + 4) = 2(z + 1)

Reorder the terms:
4(-1 + 3z) + -5(z + 4) = 2(z + 1)
(-1 * 4 + 3z * 4) + -5(z + 4) = 2(z + 1)
(-4 + 12z) + -5(z + 4) = 2(z + 1)

Reorder the terms:
-4 + 12z + -5(4 + z) = 2(z + 1)
-4 + 12z + (4 * -5 + z * -5) = 2(z + 1)
-4 + 12z + (-20 + -5z) = 2(z + 1)

Reorder the terms:
-4 + -20 + 12z + -5z = 2(z + 1)

Combine like terms: -4 + -20 = -24
-24 + 12z + -5z = 2(z + 1)

Combine like terms: 12z + -5z = 7z
-24 + 7z = 2(z + 1)

Reorder the terms:
-24 + 7z = 2(1 + z)
-24 + 7z = (1 * 2 + z * 2)
-24 + 7z = (2 + 2z)

Solving
-24 + 7z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-24 + 7z + -2z = 2 + 2z + -2z

Combine like terms: 7z + -2z = 5z
-24 + 5z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-24 + 5z = 2 + 0
-24 + 5z = 2

Add '24' to each side of the equation.
-24 + 24 + 5z = 2 + 24

Combine like terms: -24 + 24 = 0
0 + 5z = 2 + 24
5z = 2 + 24

Combine like terms: 2 + 24 = 26
5z = 26

Divide each side by '5'.
z = 5.2

Simplifying
z = 5.2

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