4(3z-1)=20

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Solution for 4(3z-1)=20 equation: 



4(3z-1)=20

We move all terms to the left:

4(3z-1)-(20)=0

We multiply parentheses

12z-4-20=0

We add all the numbers together, and all the variables

12z-24=0

We move all terms containing z to the left, all other terms to the right

12z=24

z=24/12

z=2

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