4(3z-1)=3z+68

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Solution for 4(3z-1)=3z+68 equation:


Simplifying
4(3z + -1) = 3z + 68

Reorder the terms:
4(-1 + 3z) = 3z + 68
(-1 * 4 + 3z * 4) = 3z + 68
(-4 + 12z) = 3z + 68

Reorder the terms:
-4 + 12z = 68 + 3z

Solving
-4 + 12z = 68 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-4 + 12z + -3z = 68 + 3z + -3z

Combine like terms: 12z + -3z = 9z
-4 + 9z = 68 + 3z + -3z

Combine like terms: 3z + -3z = 0
-4 + 9z = 68 + 0
-4 + 9z = 68

Add '4' to each side of the equation.
-4 + 4 + 9z = 68 + 4

Combine like terms: -4 + 4 = 0
0 + 9z = 68 + 4
9z = 68 + 4

Combine like terms: 68 + 4 = 72
9z = 72

Divide each side by '9'.
z = 8

Simplifying
z = 8

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